# Greg has a school debt of \$9875. he wants to make biweekly payments and pay off the loan in four years. if the intrest rate is 6.3% compounded biweekly, how much are his payments?

Answer: Greg would the payments of \$15,553.13. I think or \$2,222

## Related Questions

Laura's family is going on a vacation. They will drive 4,180 miles over the next two weeks miles will they drive on average each week?

On average each week they will drive 2,000 miles

Describe the transformation from the graph of f(x) = x + 4 to the graph of g(x) = x - 1

Moved 5 units right.......................

10. Ben and Joel are raising money for their class trip by selling wrapping paper. Ben raised \$43.50 by selling 12 rolls of solid paper and 9 rolls of printed paper. Joel raised \$51.50 by selling 8 rolls
of solid paper and 15 rolls of printed paper. Find the cost of each type of wrapping paper.
0, 2012

solid paper = 1.75

printed paper = 2.5

Step-by-step explanation:

Ben = \$43.50 (12 rolls solid paper and 9 rolls of printed paper)

Joel = \$51.50 (8 rolls solid paper and 15 rolls of printed paper)

Let x = solid paper

Let y = printed paper

12x + 9y = 43.50

8x + 15y = 51.50

Find x:

8x + 15y = 51.50

8x = 51.50 - 15y

x = (51.50 - 15y)/8

Substitute x:

12x + 9y = 43.50

12(51.50 - 15y)/8 + 9y = 43.50

(618 - 180y)/8 + 9y = 43.50

8 (618 - 180y)/8 + 8*9y = 43.50 * 8

618 - 180y + 72y = 348

-108y = 348 - 618

-108y = -270

-108y/-108 = -270/-108

y = 2.50

x = (51.50 - 15y)/8

x = (51.50 - 15(2.5) /8

x = (51.50 - 37.50)/8

x = 14/8

x = 1.75

To check: x = 1.75 ; y = 2.5

12x + 9y = 43.50

12(1.75) + 9(2.5) = 43.50

21 + 22.50 = 43.50

43.50 = 43.50

8x + 15y = 51.50

8(1.75) + 15(2.5) = 51.50

14 + 37.50 = 51.50

51.50 = 51.50

Is 25/99 a terminating or repeating decimal

25/99 = 0.2525252525

Do you see that 25 repeats?

Repeating decimal for sure.

What do you call the transformation(s) where the image has the same orientation as the preimage. A) translation
B) translation and glide reflection
C) glide reflection and reflection
D) rotation

"Translation" is the one among the following choices given in the question that you call the transformation(s) where the image has the same orientation as the preimage. The correct option among all the options that are given in the question is the first option or option "A". I hope the answer has helped you.
I think it would be B)

Dr. Six drives through two stoplights on her way to work. The first light is green for 20 seconds out of each minute. The second light is green for 35 seconds out of each minute. What is the probability that Dr. Six will hit two green lights?

Probability 1 * Probability 2 = Probability of both

Let minute = 60 seconds

First light probability = 20/60 (20 seconds out of each 60 seconds)
= 0.33 (recurring)

Second light probability = 35/60 (35 seconds out of each 60 seconds)
= 0.5833 (recurring)

To get a more accurate end probability use the numbers 20/60 and 35/60 appose to the rounding (on the calculator):

Using the formula at the top:
20/60 * 35/60 = 0.194  (3 DP)

The probability of that Dr. Six will hit two green lights is 0.194 (3DP)

A car is traveling at a speed of 75 km/h. Identify the correct conversion factor setup required to compute the speed of the car in m/s. A)
75km
1hr
x
1000m
1km
x
1hr
60min
x
60s
1min

B)
75km
1hr
x
1000m
1km
x
1hr
60min
x
1min
60s

C)
75km
1hr
x
1000m
75km
x
1hr
60min
x
1min
60s

D)
75km
1hr
x
1000m
75km
x
1hr
60min
x
60s
1min

9km

1hr

x

1000m

1km

x

1hr

60min

x

1min

60s

9km/1hr x 1000m/1km x 1hr/60min x 1min/60s = 2.5 m/s

If the conversion factors are properly set up and all numbers are correct, the unwanted units cancel out leaving the units of the final answer.

A rectangular field is to have an area of 100m2 and is to be surrounded by a fence. The cost C of the fence is 18 dollars per meter of length. Express the total cost of the fence in terms of the width of the field (use the variable 'w' for width).?

The total cost of the fence in terms of the width of the field is .

Given that

A rectangular field is to have an area of 100m2 and is to be surrounded by a fence.

The cost C of the fence is 18 dollars per meter in length.

We have to determine

The total cost of the fence in terms of the width of the field (use the variable 'w' for width.

According to the question

Let the total cost of the fence of the width field by W.

Area of the rectangular fence = 100 square meters.

The cost C of the fence is 18 dollars per meter in length.

Area of the rectangular field;

The perimeter of the rectangle;

The total cost of the fence in terms of the width of the field is,

Hence, the total cost of the fence in terms of the width of the field is .

brainly.com/question/26176817

Step-by-step explanation:

Let l be the length of rectangular field and w be the width of rectangular field.

Area = 100 square meter

Area of rectangular field

=

Cost of fencing =  18 dollars per meter

Perimeter of rectangle

Total cost =

is the required cost function.

Simplify the expression
4(b - 6) + 19