# a 20 kg sig is pulled by a horizontal force such that the single rope holding the sign make an angle of 21 degree with the verticle assuming the sign is motionless find the magnitude of the tension in the ropend the magnitude of the horizontal force?

T= 210.15 N

F= 75.31 N

Explanation:

Let the tension in string be T newton.

According to the question

⇒T×cos21°= mg

⇒T= mg/cos21°

⇒T=20×9.81/cos21

⇒T= 210.15 N

now, the magnitude of horizontal force

F= Tsin21°

⇒F= 210.15×sin21°

=75.31 N

## Related Questions

The graph of a line gets ________ as the value of the slope gets smaller. A. Steeper
B. Shorter
C. Less steep
D. Longer

Explanation:

The graph of a line gets less steep, the value of slope gets smaller.

The slope describes the steepness in the graph. Larger slope means steeper graph line. On the other hand, smaller graph line means that the slope is less steep. Hence, the correct answer is The graph of a line gets Less steep as the value of the slope gets smaller.

The graph of a line gets less steep as the value of the slope gets smaller.

A line is a straight one-dimensional figure having no thickness and extending infinitely in both directions. A line is sometimes called a straight line or, more archaically, a right line (Casey 1893), to emphasize that it has no "wiggles" anywhere along its length.

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

A hiker must travel 800 km. How many days will the hike take him if the hiker travels 10 h/day at a speed of 8 km/h? Step by step explanation please.

Alright so what you will want to do is multiply 8 x 10 =80 then multiply 80 x 10 =800. So it took the hiker 10 days.

A person with a near point of 120 cmbut excellent distant vision, normally wears corrective glasses. But he loses them while traveling. Fortunately, he has his old pair as a spare.a) If the lenses of the old pair have a power of +2.60 diopters , what is his near point (measured from his eye) when he is wearing the old glasses if they rest 2.00 cm in front of his eyes?front of his eye?b) What would his near point be if his old glasses were contact lenses instead?

a. 31 cm

b. 29.125 cm

Explanation:

From the glasses, the near point is

d = 120 - 2 = 118 cm (since long sighted and the objects lie 2 cm in front of his eyes as he lost the glass but has a near point of 120 cm)

The power of the lens is +2.60 diopters, so the focal length of the lens = 1/ power of lens = 1 / 2.6 = 38.46 cm

Since the image in lens is virtual, therefore, the formed image is virtual

So, the image distance is q = -d = -118 cm

using the thin lens equation, we have

1/f = 1/p + 1/q

Making p subject of the formula, we have

p = f*q/(q - f)

Hence p = 38.46*-118 / (-118 - 38.46) - equation (a)

p = 29 cm

Therefore, the near point of the person from the eye = 29 + 2 = 31 cm

B. if contact lenses were used instead, then the image distance q = -120 cm

Substitute -120 for -118 in equation (a) we have

p = 38.46*-120 / (-120 - 38.46)

= 29.125 cm

A

B

Explanation:

The symbols for elements have either

Capital or small letters

Which of the following is an accurate statement? A. Step-down voltage transformers have a different number of turns in the primary than in the secondary winding, so they change the incoming voltage to a higher voltage.
B. AC Generators produce current that is pulsating, but always remains positive.
C. DC Generators produce current with a voltage that changes from positive to negative.
D. Step-up voltage transformers have a lower number of turns in the primary than in the secondary winding.

D.
Step-up transformers should have more turns in the second winding to increase the voltage of the incoming voltage.

A 1,160 kg satellite orbits Earth with a tangential speed of 7,446 m/s. If the satellite experiences a centripetal force of 8,955 N, what is the height of the satellite above the surface of Earth? Recall that Earth’s radius is 6.38 × 106 m and Earth’s mass is 5.97 × 1024 kg.

Answer: The height of the satellite above the surface of Earth is

Explanation:

Given

Mass of the satellite, m= 1160 kg

tangential speed , v = 7446 m/s

Centripetal force , F = 8955 N

Radius of earth , R= m

Let height of satellite above surface of the Earth be H

Centripetal force on satellite is given by

=>

=>

Thus the height of the satellite above the surface of Earth is

Explanation:

Let the height above the surface of Earth is H

now we know that gravitational force due to Earth on the satellite is net centripetal force due to which it is revolving around the Earth

So we can say

now we know that

1.5 m3 of water is mixed with 0.50 m3 of alcohol. The density of water is 1000 kg m–3 and the density of alcohol is 800 kg m–3. What is the density of the mixture with volume 2.0 m3?

The density of the mixture containing 1.5 m³ of water and 0.50 m³ alcohol is 950 Kgm¯³

Density is simply defined as the mass per unit volume of the substance i.e

Density = mass / volume

To obtain the density of the mixture, we'll begin by calculating the mass of the water and alcohol.

For Water:

Volume of water = 1.5 m³

Density of water = 1000 Kgm¯³

Mass of water =?

Mass = Density × Volume

Mass of water = 1000 × 1.5

Mass of water = 1500 Kg

For Alcohol:

Volume of alcohol = 0.50 m³

Density of alcohol = 800 Kgm¯³

Mass of alcohol =?

Mass = Density × Volume

Mass of alcohol = 800 × 0.5

Mass of alcohol = 400 Kg

Next, we shall determine the mass of the mixture.

Mass of water = 1500 Kg

Mass of alcohol = 400 Kg

Mass of mixture =?

Mass of mixture = (Mass of water) + (Mass of alcohol)

Mass of mixture = 1500 + 400

Mass of mixture = 1900 Kg

Finally, we shall determine the density of the mixture.

Mass of mixture = 1900 Kg

Volume of mixture = 2 m³

Density of mixture =?

Density = mass / volume

Density of mixture = 1900 / 2

Density of mixture = 950 Kgm¯³

Therefore, the density of the mixture is 950 Kgm¯³

Mass of water = 1.5*1000=1500kg
Mass of alcohol= 0.5*800=400kg
Total mass of mixture= 400kg+1500kg=1900kg
Density= 1900kg/2= 950kg/m^3

A rock is suspended from a string, and it accelerates downward. Which one of the following statements is correct? Group of answer choices a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
b. The magnitude of the tension in the string is independent of the magnitude of the rock's acceleration..
c. The magnitude of the tension in the string is equal to the magnitude of the weight of the rock.
d. The string pushes downward on the rock.
e. The magnitude of the tension in the string is less than the magnitude of the weight of the rock.

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

Explanation:

During the motion of the rock while it is in downward motion we can say

since it is performing circular motion so we will have its acceleration towards its center

So at the lowest point of the path we can say