# How many calories are required to melt a 10g ice cube which is at 0° C? 10 cal 80 cal 800 cal 540 cal

Answer: 800 calories are required to melt a 10g ice cube which is at 0 degrees C.

## Related Questions

How many atoms of aluminum AL are in 2.75 mol of aluminum

Answer: 1.66 x 10^24 atom

Explanation: 1mole of Al contains 6.02x10^23 atoms.

Therefore, 2.75moles of Al will contain = 2.75 x 6.02x10^23 = 1.66 x 10^24 atom

An isomer with a branched structure will require:

The  branched  structure  isomer  will require   less  energy  to  melt  than the straight  chain  isomer

explanation
Branched  structure  isomer    has  weak  intermolecular  forces  of attraction  as  compared  to  straight  chain  isomers.  In addition the  branched  isomer  has  a  low boiling point as  compared to  straight chain isomers. Since   boiling require  the of  the  intermolecular  forces tend to have  lower  boiling  point   than straight chain

The chemical reaction of photosynthesis naturally occurs in the presence of sunlight because the light.....

helps in photosynthesis

Explanation:

when there is the presence of light the photosynthesis is dine

A 22.5-g sample of ice at - 10.0°C is mixed with 110.0 g water at 85.0°C. Calculate the final temperature of the mixture assuming no heat loss to the surroundings. The heat capacities for H₂O(l) and H₂O(s) are 4.18 J/g･°C and 2.03 J/g･°C, respectively, and the enthalpy of fusion of ice is 6.02 kJ/mol.

The answer to the question is

56.166 °C

Explanation:

To solve the question, we list out the varibles as follws

Mass of ice, mi = 22.5 g

Mass of warer, mw = 110 g

Initial temperature of the ice = - 10.0 °C

Initial temperature of the water = 85.0°C

Specific heat capacity of ice, ci = 2.03 J/g･°C

Specific heat capacity of water, cw = 4.18 J/g･°C

Enthalpy of fusion of ice = 6.02 kJ/mol.

From the first law of thermodynamics we have

Heat lost by the water = heat gained by the ice

mi×ci×ΔTi +mi×L = mw×cw×ΔTw

22.5 g × 2.03 J/g･°C × (0 -(-10))°C + 22.5 g/(18.01528 g/mol) × 6.02 kJ/mol ×1000 + 22.5 g × 4.18 J/g･°C × T= 110.0 g × 4.18 J/g･°C × ( 85.0°C - T)

7975.4 + 94.05 T = 39083 - 459.8T

Making T the subject of the formula we have

553.85 T =  31107.6 or T = 56.166 °C

The final temperature of the mixture = 56.166 °C

Build molecular models of cyclobutane and cyclcopentane. a. what are the approximate bond angles in each

Answer is: the approximate bond angle in cyclobutane is 90 degrees and in cyclopentane is 108 degrees.

Cyclobutane has single covalent bonds, the actual C-C-C bond angle is 88 degrees, because it has a slightly folded form to relieve some torsional strain.
Cyclopentane also has single covalent bonds and it has an unfixed puckered shape that undulates up and down.

Why don't noble gases normally form chemical bonds?

Noble gases already have a full outer valence shell...whcih can only hold a maximum of 8 electrons. since the outer shell is filled, it doesn't have any empty electron spaces to form chemical bonds with other elements

How many significant figures does the rounded ans 101 cm - 99.1 cm = 1.9 cm (unrounded) After rounding, the answer should be reported to the and thus has 0.5 atm + 9.8 atm = 10.3 atm (unrounded) After rounding, the answer should be reported to the and thus has

Explanation:

Rules for counting significant figures:

1. Digits from 1 to 9 are always significant and have infinite number of significant figures.
2. All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
3. All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
4. All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.

1) 101 cm - 99.1 cm = 1.9 cm ≈ 2.0 cm

1.9 cm ≈ 2.0 cm

There are two significant figures that is 2 and 0.

2) 0.5 atm + 9.8 atm = 10.3 atm ≈ 10.0 atm

There are three significant figures that is 3 , 0 and 0.

A sample of wood with a mass of 3.0 grams was burned in an open dish. The ashes weighed 1.2 grams.

The 1.8 grams was converted to gaseous compounds

Explanation:

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The remaining 1.8 grams was converted into gaseous compounds.

Explanation:

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Definition of electron