# Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18(l) + 25 O2( g. → 16 CO2( g. + 18 H2O( g.

In a chemical reaction, the maximum amount of the product that can be formed is called the theoretical yield. This along with the actual yield gives the percentage yield.

2.56 moles theoretical yield.

How to calculate the theoretical yield?

Given,

• Moles of = 4 moles
• Moles of = 4 moles
• The molar mass of the =

The balanced chemical reaction can be shown as,

From the reaction, it can be said that,

25 moles of oxygen reacts with 2 moles of

So, 4 moles of oxygen = X moles of

From this, it can be said that oxygen is the limiting reagent.

25 moles of Oxygen = 16 moles of

4 moles of Oxygen = X moles of

Therefore, 2.56 moles of Carbon dioxide is produced.

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Theoretical yield = 2.56  moles of CO₂

Explanation:

2 C₈H₁₈(l) + 25 O₂( g) → 16 CO₂( g) + 18 H₈O( g)

As per the given balanced equation 2 moles of C₈H₁₈ combines with 25 moles of O₂. So 4 moles of of C₈H₁₈ requires 50 moles of O₂. But in the given question we have 4 moles of O₂ there O₂ is the limiting reagent.

The limiting reagent determines the yield of the product. Therefore, here O₂ will determines the yield of CO₂.

As per the given balanced equation 25 moles of O₂ yields 16 moles of CO₂.

Therefore, 4 moles of O₂ will yield ( x 4 ) moles of CO₂

= 2.56  moles of CO₂

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